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NEW QUESTION: 1
Ann, a home user, brings a Windows XP PC in for repair and reports that several disk read errors are occurring. She has run check disk and errors have been reported several times. Which of the following should a technician recommend? (Select TWO).
A. Upgrade to a home server
B. Upgrade to Windows 7 Professional
C. Backup all data on the drive
D. Increase the amount of RAM to improve disk checks
E. Change the drive configuration to RAID 0
F. Purchase a new hard drive
Answer: C,F
Explanation:
First backup all the data from the drive to prevent data loss. Get a new hard drive and restore the data on the new drive.

NEW QUESTION: 2
You use Microsoft SQL Server 2012 to develop a database that has two tables named Div1Cust and Div2Cust. Each table has columns named DivisionID and CustomerId . None of the rows in Div1Cust exist in Div2Cust. You need to write a query that meets the following requirements:
The rows in Div1Cust must be combined with the rows in Div2Cust.
The result set must have columns named Division and Customer.
Duplicates must be retained.
Which three Transact-SQL statements should you use? (To answer, move the appropriate statements from the list of statements to the answer area and arrange them in the correct order.)
Build List and Reorder:

Answer:
Explanation:

Explanation:
--Burgos - NO
Reference: http://msdn.microsoft.com/en-us/library/ms180026.aspx Reference: http://msdn.microsoft.com/en-us/library/ms188055.aspx

NEW QUESTION: 3
John works as a project manager of the NHQ Project. He has created the project network diagram as shown in the figure:

Based on the project network diagram, how much float is available for Activity H if Activity B is delayed by four days and Activity E is delayed by two days?
A. Five
B. Four
C. One
D. Zero
Answer: D
Explanation:
Explanation/Reference:
Explanation:
The path of ABEHJ will take 22 days to complete and cannot exceed 28 days or else the project will be late. If Activity B takes four additional days and Activity E takes two additional days, this adds (4+2= 6) six days to the path, bringing the path's duration to exactly (22+6 = 28) days. There is no available float left for Activity D or H. Float or total float (TF) is the total amount of time that a schedule activity may be delayed from its early start date without delaying the project finish date, or violating a schedule constraint. It is calculated by using the critical path method technique and determining the difference between the early finish dates and late finish dates.
Incorrect Answers:
B, C, D: There is no float available because the path's duration has increased to 28 days.