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NEW QUESTION: 1

A. SELECT COUNT(*) FROM Purchases WHERE PurchaseTime = CONVERT(DATE, GETDATE())
B. SELECT COUNT(*) FROM Purchases WHERE CONVERT(VARCHAR, PurchaseTime, 112) = CONVERT(VARCHAR, GETDATE(), 112)
C. SELECT COUNT(*) FROM Purchases WHERE PurchaseTime >= CONVERT(DATE, GETDATE())
AND PurchaseTime < DATEADD(DAY, 1, CONVERT(DATE, GETDATE()))
D. SELECT COUNT(*) FROM Purchases WHERE PurchaseTime = GETDATE()
Answer: C
Explanation:
Two answers will return the correct results (the "WHERE CONVERT..." and "WHERE ... AND ... " answers).
The correct answer for Microsoft would be the answer that is most "efficient". Anybody have a clue as to which is most efficient? In the execution plan, the one that I've selected as the correct answer is the query with the shortest duration. Also, the query answer with "WHERE CONVERT..." threw warnings in the execution plan...something about affecting CardinalityEstimate and SeekPlan.
I also found this article, which leads me to believe that I have the correct answer:
http://technet.microsoft.com/en-us/library/ms181034.aspx

NEW QUESTION: 2

A. Option A
B. Option D
C. Option C
D. Option B
Answer: C

NEW QUESTION: 3
あなたは、5 GHzスペクトラムで高いユーザー密度をサポートするように無線ネットワークを設計しています。より広いチャネル幅を選択する代わりに20 MHzのチャネル幅を選択することの利点は、どのオプションですか？
A. 減速
B. 広帯域
C. 同一チャネル干渉の減少
D. スループット向上
Answer: C
Explanation:
説明/参照：
Explanation:
5 GHzチャネルの再利用を余儀なくされた場合、厳密に20 MHzチャネルを使用してCCIによる効率の低下を回避しながら、より一貫した結果が得られます。
https://www.cisco.com/c/en/us/products/collateral/wireless/aironet-1250-series/design_guide_c07-
693245.html＃_Toc309331077