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NEW QUESTION: 1
次の表に示すようにサーバーが構成されています。

ネットワークは10.10.0.0/24の内部アドレススペースを使用しています。 クライアントコンピュータからアドレスが割り当てられている
10.10.0.60から10.10.0.199。
Server4には、次の表に示すIPv4構成があります。

ネットワーク上のコンピューターへのインターネットアクセスを提供するようにServer4を構成する必要があります。
どの3つのアクションを順番に実行しますか？ 回答するには、適切な行動を行動のリストから回答領域に移動し、正しい順序で配置します。

Answer:
Explanation:

1 - Install the Remote Access server role.
2 - Open the Routing and Remote Access console.
3 - Run the Routing and Remote Access Server Setup Wizard. Add 131.12.11.121 to the NAT interface.

NEW QUESTION: 2
OSPFを実行し、ネットワークを追加するようにルーターを適切に構成するために必要なコマンド
192.168.16.0/24からOSPFエリア0？ （2つ選択してください。）
A. Router(config)# router ospf 1
B. Router(config)# router ospf 0
C. Router(config-router)# network 192.168.16.0 0.0.0.255 area 0
D. Router(config)# router ospf area 0
E. Router(config-router)# network 192.168.16.0 255.255.255.0 area 0
F. Router(config-router)# network 192.168.16.0 0.0.0.255 0
Answer: A,C
Explanation:
ルーターOSPFで
コマンドの範囲は1〜65535です。oは無効な数字です->しかしOSPFを設定するには、サブネットマスクではなく、「ネットワーク」ステートメントにワイルドカードが必要です。また、このプロセスに領域を割り当てる必要があります->。

NEW QUESTION: 3
Refer to the exhibit.

ROUTE.com has just implemented this EIGRP network. A network administrator came to you for advice while trying to implement load balancing across part of their EIGRP network.
If the variance value is configured as 2 on all routers and all other metric and K values are configured to their default values, traffic from the Internet to the data center will be load balanced across how many paths?
A. 0
B. 1
C. 2
D. 3
E. 4
Answer: D
Explanation:
Explanation First we should list all the paths from the Internet to the data center:
+
A-B-C-H with a metric of 70 (40 + 15 + 15)+ A-B-E-H with a metric of 60 (40+10+10)+ A-D-E-H with a metric of 30 (10+10+10)+ A-D-E-B-C-H with a metric of 60 (10+10+10+15+15)+ A-D-E-FG-H with a metric of 70 (10+10+10+20+20)+ A-F-G-H with a metric of 60 (20+20+20)+ A-F-E-H with a metric of 40 (20+10+10) So the path A-D-E-H will be chosen because it has the best metric. But EIGRP can support unequal cost path load balancing. By configuring the variance value of 2, the minimum metric is increased to 60 (30 * 2) and all the routes that have a metric of less than or equal to 60 and satisfy the feasibility condition will be used to send traffic. Besides the main path A-D-E-H we have 4 more paths that have the metric of less than or equal to 60 (we also include the Advertised Distances of these routes for later comparison):
+
A-B-E-H with an AD of 20+ A-D-E-B-C-H with an AD of 50+ A-F-G-H with an AD of 40+ A-F-E-H with an AD of 20 Now the last thing we need to consider is the feasible condition. The feasible condition states:
"To qualify as a feasible successor, a router must have an AD less than the FD of the current successor route"
The FD of the current successor route here is 30 (notice that the variance number is not calculated here). Therefore there are only 2 paths that can satisfy this conditions: the path A-B-E-H & A-F-E
H.In conclusion, traffic from the Internet to the data center will be load balanced across 3 paths,
including the main path (successor path)

NEW QUESTION: 4
Which three statements about dynamic filtering are true? (Choose three.)
A. Dynamic filtering creates a query statement.
B. Dynamic filtering has an option to save query.
C. Dynamic filtering can select any log field to filter.
D. Dynamic filtering permanently removes other log entries.
E. Dynamic filtering redraws the log when you select a variable link.
Answer: A,B,E