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NEW QUESTION: 1
You are reviewing a design for a database. A portion of this design is shown in the exhibit. Note that you may choose to view either the Crow's Foot Notation or Chen Notation version of the design. (To view the Crow's Foot Notation, click the Exhibit A button. To view the Chen Notation, click the Exhibit B button.)

Which term is used to describe the relationship between Customer and Order?
A. one-to-many
B. one-dimensional
C. one-to-one
D. many-to-many
E. multi-dimensional
Answer: A
Explanation:
A customer can have many orders.

NEW QUESTION: 2
Given:
1 . interface A { }
2 . interface B { void b(); }
3 . interface C { public void c(); }
4 . abstract class D implements A,B,C { }
5 . class E extends D {
6 . void b() { }
7 . public void c() { }
8 . }
Which is true?
A. The code compiles without error.
B. Compilation fails due to an error in line 6.
C. Compilation fails due to an error in line 1.
D. Compilation fails due to an error in line 2.
E. Compilation fails due to an error in line 4.
Answer: B

NEW QUESTION: 3
Refer to the exhibit. This exhibit shows the NAT configuration for Router A and the output for a ping issued from device 171.68.200.48 and destined to 172.16.47.142. Based on this information, what change must be made to Router A in order for the ping to work?

A. clear the route cache
B. configure IP as classless
C. reload the router
D. add a static route
E. load a newer IOS image
Answer: B
Explanation:
The assumption with classful routing is that all of a classful address belongs to one organization. The idea of a component subnet would be any subnet of a classful network. When you look at the routing table it lists the subnets based on the classful networks like this: Network 192.168.1.0/27 is subnetted 2 subnets 192.168.1.32 .... 192.168.1.64 .... The
192.168.1.32 and 192.168.1.64 subnets would be the "component subnets" of the
192.168.1.0 network. So the point is that if you tried to route a packet to 192.168.1.151 it would be dropped even if there was a default route in the routing table. The reason fo this is that the router knows of subnets that belong to the major network (192.168.1.0 in this case), but does not have an entry for the specific subnet.