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NEW QUESTION: 1
A network administrator is configuring the routers in the graphic for OSPF. The OSPF process has been started and the networks have been configured for Area 0 as shown in the diagram. The network administrator has several options for configuring RouterB to ensure that it will be preferred as the designated router (DR) for the 172.16.1.0 /24 LAN segment.
What configuration tasks could be used to establish this preference? (Choose three.)

A. Configure the priority value of the Fa0/0 interface of RouterB to a higher value than any other interface on the Ethernet network.
B. Configure a loopback interface on RouterB with an IP address higher than any IP address on the other routers.
C. No further configuration is necessary.
D. Change the priority value of the Fa0/0 interface of RouterB to zero.
E. Change the priority values of the Fa0/0 interfaces of RouterA and RouterC to zero.
F. Change the router id of Router B by assigning the IP address 172.16.1.130/24 to the Fa0/0 interface of RouterB.
Answer: A,B,E

NEW QUESTION: 2
転記された請求書でどのフィールドを変更できますか？
A. Special G/L indicator
B. Tax code
C. Cost center
D. Payment terms
Answer: D

NEW QUESTION: 3
Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
A. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
B. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
C. The network is not subnetted.
D. The subnet address is 10.16.3.0 255.255.254.0.
E. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
Answer: B,E
Explanation:
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits. The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to 254. The host 10.16.3.65 is in the 2.0 subnet.
The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254