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NEW QUESTION: 1
You are the administrator for a Master Data Services (MDS) environment.
A user who is not an administrator must be able to access Master Data Manager.
You need to assign permissions to the user.
Which function should you use?
A. Explorer
B. Version Management
C. Integration Management
D. System Administration
E. User and Group Permissions
Answer: E
Explanation:
Explanation
In the User and Group Permissions functional area, administrators can grant permission to functional areas, to attributes (on the Models tab), and to members (on the Hierarchy Members tab). Overlapping permissions are resolved to determine a user's permission to each individual attribute.
References:
https://docs.microsoft.com/en-us/sql/master-data-services/user-and-group-permissions-functional-area-master-da

NEW QUESTION: 2
In a derive node, which expressions will produce a continuous data type rather than a string? (Select all that apply)
A. Datetime_date(2008.05.22)
B. "2001-04-23"
C. "03/15/2009"
D. To_date("12/01/2050")
Answer: D

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(OrderAmount) DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
B. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM (SELECT c.CustomerID, c.CustomerName, o.ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk FROM Customer c INNER JOIN Orders o ON c.CustomerID = o.CustomerID GROUP BY c.CustomerID, c.CustomerName, o.ShippingCountry) cs WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, COUNT(OrderAmount) DESC) AS OrderAmount FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry FROM Customer c INNER JOIN (SELECT CustomerID, ShippingCountry, RANK() OVER (PARTITION BY CustomerID ORDER BY OrderAmount DESC) AS Rnk FROM Orders GROUP BY CustomerID, ShippingCountry) AS o ON c.CustomerID = o.CustomerID WHERE o.Rnk = 1
Answer: A

NEW QUESTION: 4
What are the three service provider business models?
A. Internal service provider, outsourced 3rd party and off-shore party
B. Internal service operations provider, external service operations provider, shared service unit
C. Internal service provider, external service provider, shared service unit
D. Internal service provider, external service provider, outsourced 3rd party
Answer: C
Explanation:
Explanation/Reference:
Explanation: