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NEW QUESTION: 1
Which represents the MOST important business continuity risk?
A. Incomplete Service Level Agreements (SLAs)
B. Privacy laws
C. Providers going out of business
D. Network connectivity interruption
Answer: C

NEW QUESTION: 2
Given the code fragment:

What is the result?
A. 4000 : 1000
B. 1000 : 2000
C. 4000 : 2000
D. 1000 : 4000
Answer: A

NEW QUESTION: 3
Examine the structure of the EMPLOYEES table.
NameNull?Type
---------------------- ------------
EMPLOYEE_IDNOT NULLNUMBER(6)
FIRST_NAMEVARCHAR2(20)
LAST_NAMENOT NULLVARCHAR2(25)
EMAILNOT NULLVARCHAR2(25)
PHONE NUMBERVARCHAR2(20)
HIRE_DATENOT NULLDATE
JOB_IDNOT NULLVARCHAR2(10)
SALARYNUMBER(8,2)
COMMISSION_PCTNUMBER(2,2)
MANAGER_IDNUMBER(6)
DEPARTMENT_IDNUMBER(4)
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the last names and manager IDs of employees who work for the same manager as the employee whose EMPLOYEE_ID is 123.
Which query provides the correct output?
A. SELECT m.last_name, e.manager_idFROM employees e LEFT OUTER JOIN
employees mon (e.manager_id = m.manager_id)WHERE e.employee_id = 123;
B. SELECT e.last_name, e.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.employee_id = m.employee_id)WHERE e.employee_id = 123;
C. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.employee_id = m.manager_id)WHERE e.employee_id = 123;
D. SELECT e.last_name, m.manager_idFROM employees e RIGHT OUTER JOIN
employees mon (e.manager_id = m.employee_id)AND e.employee_id = 123;
Answer: C