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NEW QUESTION: 1
ソリューションアーキテクトは、AWS Fargateで実行されるコンテナ化されたNET Coreアプリケーションを構築しています。アプリケーションのバックエンドには高可用性のMicrosoft SQL Serverが必要ですアプリケーションのすべての層は高可用性である必要がありますSQL Serverへの接続文字列に使用される資格情報は.NET Coreフロントエンドコンテナー内のディスクに格納されます。
これらの要件を満たすために、ソリューションアーキテクトはどの戦略を使用する必要がありますか？
A. Amazon EC2でSQL Serverを実行するAuto Scalingグループを作成するAWSシークレットマネージャーでEC2で実行されているSQL Serverの認証情報のシークレットを作成するFargateタスク定義がシークレット値を取得できるようにするAmazon ECSタスク実行ロールを作成しますEC2上のSQL Serverへの認証情報の場合Fargateタスク定義のsecretsセクションでシークレットm Secrets ManagerのARNを指定します。これにより、起動時に環境変数として機密データをコンテナに注入し、アプリケーションに読み込んで接続を構築できます。 string複数のアベイラビリティーゾーンでApplication Load Balancerの背後にあるService Auto Scalingを使用してNET Coreサービスを設定します。
B. SQL Serverを設定して、サービスのAuto Scalingを備えたFargateで実行します。 Fargateタスク定義がFargateで実行されているSQL Serverへの認証情報のシークレット値を取得できるようにするAmazon ECSタスク実行ロールを作成するFargateタスク定義のシークレットセクションでAWS Secrets ManagerのシークレットのARNを指定して、機密データを起動時に環境変数としてコンテナに注入し、アプリケーションに読み込んで接続文字列を作成できます。複数のアベイラビリティーゾーンでApplication Load Balancerの背後にあるサービスAuto Scalingを使用してNET Coreサービスをセットアップします。
C. Amazon RDSでSQL ServerのマルチAZ配置を作成しますRDSデータベースへの認証情報用にAWSシークレットマネージャーでシークレットを作成しますFargateタスク定義でNET Coreコンテナー用の非永続的な空のストレージを作成し、機密情報を保存します情報Fargateタスク定義が秘密鍵マネージャーのRDSデータベースへの認証情報の秘密の値を取得できるようにするAmazon ECSタスク実行ロールを作成します。秘密鍵のARNをFargateタスク定義の秘密セクションで秘密鍵マネージャーに指定します。起動時にデータを非永続的な空のストレージに書き込んで、アプリケーションに読み込んで接続文字列を作成できます。複数のアベイラビリティーゾーンでApplication Load Balancerの背後にあるService Auto Scalingを使用してNET Coreサービスを設定します。
D. Amazon RDSでSQL ServerのマルチAZ配置を作成します。RDSデータベースへの認証情報のためにAWSシークレットマネージャーでシークレットを作成します。Amazonを作成します。
Fargateタスク定義が秘密鍵マネージャーのRDSデータベースへの資格情報の秘密値を取得できるようにするECSタスク実行ロールFargateタスク定義の秘密セクションで秘密鍵マネージャーの秘密のARNを指定して、機密データを注入できるようにします複数のアベイラビリティーゾーンでApplication Load Balancerの背後にあるサービスのAuto Scalingを使用して、FargateでNET Coreサービスを設定し、接続文字列を構築するために起動時に環境変数としてコンテナーに入力します。
Answer: D
Explanation:
Explanation
https://aws.amazon.com/premiumsupport/knowledge-center/ecs-data-security-container-task/

NEW QUESTION: 2
CORRECT TEXT
JS Industries has expanded their business with the addition of their first remote office. The remote office router (R3) was previously configured and all corporate subnets were reachable from R3. JS Industries is interested in using route summarization along with the EIGRP Stub Routing feature to increase network stability while reducing the memory usage and bandwidth utilization to R3. Another network professional was tasked with implementing this solution. However, in the process of configuring EIGRP stub routing connectivity with the remote network devices off of R3 has been lost.
Currently EIGRP is configured on all routers R2, R3, and R4 in the network. Your task is to identify and resolve the cause of connectivity failure with the remote office router R3. Once the issue has been resolved you should complete the task by configuring route summarization only to the remote office router R3.
You have corrected the fault when pings from R2 to the R3 LAN interface are successful, and the R3 IP routing table only contains 2 10.0.0.0 subnets.




Answer:
Explanation:
Here are the solution as below:
Explanation:
First we have to figure out why R3 and R4 can not communicate with each other. Use the show running-config command on router R3.

Notice that R3 is configured as a stub receive-only router. The receive-only keyword will restrict the router from sharing any of its routes with any other router in that EIGRP autonomous system. This keyword will also prevent any type of route from being sent.
Therefore we will remove this command and replace it with the eigrp stub command:
R3# configure terminal R3(config)# router eigrp 123 R3(config-router)# no eigrp stub receive-only R3(config-router)# eigrp stub R3(config-router)# end Now R3 will send updates containing its connected and summary routes to other routers.
Notice that the eigrp stub command equals to the eigrp stub connected summary because the connected and summary options are enabled by default.
Next we will configure router R3 so that it has only 2 subnets of 10.0.0.0 network. Use the show ip route command on R3 to view its routing table:

Because we want the routing table of R3 only have 2 subnets so we have to summary sub- networks at the interface which is connected with R3, the s0/0 interface of R4.
There is one interesting thing about the output of the show ip route shown above: the
10.2.3.0/24, which is a directly connected network of R3. We can't get rid of it in the routing table no matter what technique we use to summary the networks. Therefore, to make the routing table of R3 has only 2 subnets we have to summary other subnets into one subnet.
In the output if we don't see the summary line (like 10.0.0.0/8 is a summary...) then we should use the command ip summary-address eigrp 123 10.2.0.0 255.255.0.0 so that all the ping can work well.
In conclusion, we will use the ip summary-address eigrp 123 10.2.0.0 255.255.0.0 at the interface s0/0 of R4 to summary.
R4> enable R4# conf t
R4(config)# interface s0/0 R4(config-if)# ip summary-address eigrp 123 10.2.0.0
255.255.0.0
Now we jump back to R3 and use the show ip route command to verify the effect, the output is shown below:

Note: Please notice that the IP addresses and the subnet masks in your real exam might be different so you might use different ones to solve this question.
Just for your information, notice that if you use another network than 10.0.0.0/8 to summary, for example, if you use the command ip summary-address eigrp 123 10.2.0.0
255.255.0.0 you will leave a /16 network in the output of the show ip route command.

But in your real exam, if you don't see the line "10.0.0.0/8 is a summary, Null0" then you can summarize using the network 10.2.0.0/16. This summarization is better because all the pings can work well.
Finally don't forget to use the copy run start command on routers R3 and R4 to save the configurations.
R3(config-if)# end
R3# copy run start
R4(config-if)# end
R4# copy run start
If the "copy run start" command doesn't work then use "write memory."

NEW QUESTION: 3
You need to store product quantities, and you want to minimize the amount of storage space that is used.
Which data type should you use?
A. COUNT
B. DOUBLE
C. FLOAT
D. INTEGER
Answer: D