Palo Alto Networks SSE-Engineer Q&A - in .pdf

  • SSE-Engineer pdf
  • Exam Code: SSE-Engineer
  • Exam Name: Palo Alto Networks Security Service Edge Engineer
  • PDF Version: V19.35
  • Q & A: 365 Questions and Answers
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NEW QUESTION: 1
SIMULATION
The number of attendees at a certain annual conference is 256 this year and has always doubled every five years. How many people attended the conference 20 years ago?
Click on the answer box, then type in a number. Backspace to erase.
Answer:
Explanation:
16
Explanation/Reference:
Explanation:
Divide by 2 four times, as follows:
5 years ago: 128
10 years ago: 64
15 years ago: 62
20 years ago: 16

NEW QUESTION: 2
다음 중 조직의 IT 거버넌스 구조를 검토하는 IS 감사인에게 가장 우려되는 사항은 무엇입니까?
A. 최고 정보 책임자는 IT와 관련된 자본 결정을 내릴 수 없습니다.
B. 최고 리스크 책임자는 최고 정보 책임자이기도 합니다.
C. IT 운영 위원회가 IT 예산을 감독합니다.
D. 이 사회에서 기대하는 IT 주제는 없습니다.
Answer: B

NEW QUESTION: 3
Given the code fragment:
public class App {
public static void main (String [] args) {
path path = paths.get("C\\educations\\institute\\student\\report.txt");
system.out.printIn("getName(0): %s", path.getName(0));
system.out.prinIn("subpath(0, 2): %s" path.subpath(0, 2));
}
}
What is the result?
A. getName (0): C:\
subpath(0, 2): education\institute
B. getName(0): report.txt subpath (0, 2): institute\student
C. getName(0): education subpath(0, 2): education\institute
D. getName(0): education
subpath(0, 2: education\institute\student
E. getName (0): C:\
subpath(0, 2): C:\education\report.txt
Answer: C
Explanation:
The getName(int index) method returns a name element of this path as a Path object.
The subpath(int beginIndex, int endIndex) method returns a relative Path that is a subsequence of the name elements of this path.
Reference: java.nio.file.Path

NEW QUESTION: 4
Microsoft 365 Enterpriseサブスクリプションがあります。
次の展示に示すように、パスワードポリシーを作成します。

ドロップダウンメニューを使用して、図に示されている情報に基づいて各ステートメントを完成させる回答の選択肢を選択します。
注:それぞれの正しい選択には1ポイントの価値があります。

Answer:
Explanation:

Explanation

By default, smart lockout locks the account from sign-in attempts for one minute after 10 failed attempts. In this question, the lockout threshold if 5 failed attempts. The account locks again after each subsequent failed sign-in attempt, for one minute at first and longer in subsequent attempts.
Password evaluation goes through several steps including normalization and Substring matching which is used on the normalized password to check for the user's first and last name as well as the tenant name.
The next step is to identify all instances of banned passwords in the user's normalized new password. Then:
* Each banned password that is found in a user's password is given one point.
* Each remaining unique character is given one point.
* A password must be at least five (5) points for it to be accepted.
Conto$01Pa$$word contains two banned passwords and no remaining unique characters so is given a score of
2 points. This is less than the required 5 points so will be rejected.
Pa$$w0rd contains a banned password and no remaining unique characters so is given a score of 1 point. This is less than the required 5 points so will be rejected.
AzureAD!!111 contains a banned password (AzureAD!!) and has three remaining characters. However, the remaining characters are all the same (they're all 1s) so that is only one unique character. So that password will be given a score of 2. One for the banned password and 1 for the unique character. This is less than the required 5 points so will be rejected.
Password11 does not contain a banned password. Password11 contains 10 characters. However, there are two
's' and two '1' so there are 8 unique characters. Therefore, the password will be given a score of 8 points. This is more than the required 5 points so the password will be accepted.
Reference:
https://docs.microsoft.com/en-us/azure/active-directory/authentication/concept-password-ban-bad
https://docs.microsoft.com/en-us/azure/active-directory/authentication/howto-password-smart-lockout

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